(5x^3-4x^2-12x)/(2x^2-10x+12)

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Solution for (5x^3-4x^2-12x)/(2x^2-10x+12) equation:


D( x )

2*x^2-(10*x)+12 = 0

2*x^2-(10*x)+12 = 0

2*x^2-(10*x)+12 = 0

2*x^2-10*x+12 = 0

2*x^2-10*x+12 = 0

DELTA = (-10)^2-(2*4*12)

DELTA = 4

DELTA > 0

x = (4^(1/2)+10)/(2*2) or x = (10-4^(1/2))/(2*2)

x = 3 or x = 2

x in (-oo:2) U (2:3) U (3:+oo)

(5*x^3-(4*x^2)-(12*x))/(2*x^2-(10*x)+12) = 0

(5*x^3-4*x^2-12*x)/(2*x^2-10*x+12) = 0

5*x^3-4*x^2-12*x = 0

x*(5*x^2-4*x-12) = 0

5*x^2-4*x-12 = 0

DELTA = (-4)^2-(-12*4*5)

DELTA = 256

DELTA > 0

x = (256^(1/2)+4)/(2*5) or x = (4-256^(1/2))/(2*5)

x = 2 or x = -6/5

x*(x+6/5)*(x-2) = 0

2*x^2-10*x+12 = 0

2*(x^2-5*x+6) = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

2*(x-2)*(x-3) = 0

(x*(x+6/5)*(x-2))/(2*(x-2)*(x-3)) = 0

( x+6/5 )

x+6/5 = 0 // - 6/5

x = -6/5

( x-2 )

x-2 = 0 // + 2

x = 2

( x )

x = 0

x in { 2}

x in { -6/5, 0 }

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